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Two triangles ABC and DBC lie on the same side of the base BC. From a point P on BC, PQ||AB and PR||BD are drawn. They meet AC in Q and DC
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Pythagorean Theorem Formula, Derivation, and solved examples
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Question 3 - ABC and DBC are two triangles on same base BC
In the given figure, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that Ar(ABC)Ar (DBC) = AODO
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Question 3 - ABC and DBC are two triangles on same base BC
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